What is the probability of failure on demand for a control valve with a dangerous failure rate of once in five years, tested every five years?

Get ready for the Functional Safety Test with multiple choice questions and explanatory answers. Enhance your knowledge and ensure you're fully prepared for your certification exam.

Multiple Choice

What is the probability of failure on demand for a control valve with a dangerous failure rate of once in five years, tested every five years?

To determine the probability of failure on demand for a control valve with a given dangerous failure rate, we need to consider the rate of failure and the testing frequency. In this case, the valve has a dangerous failure rate of one failure every five years, meaning it is expected to fail once in that timeframe. When a component is tested every five years, it has a certain probability of not failing between tests. If we define the dangerous failure rate as a constant, the probability of failure on demand can be calculated using the formula: P(failure on demand) = 1 - e^(-λt) Where λ is the failure rate (in this case, 1/5 years = 0.2 failures per year) and t is the time between tests (5 years). Plugging in these values gives: P(failure on demand) = 1 - e^(-0.2 * 5) = 1 - e^(-1) = 1 - 0.3679 ≈ 0.6321 This computation reveals that the probability of failure on demand for the control valve, when tested every five years and with a dangerous failure rate of one every five years, is approximately

To determine the probability of failure on demand for a control valve with a given dangerous failure rate, we need to consider the rate of failure and the testing frequency. In this case, the valve has a dangerous failure rate of one failure every five years, meaning it is expected to fail once in that timeframe.

When a component is tested every five years, it has a certain probability of not failing between tests. If we define the dangerous failure rate as a constant, the probability of failure on demand can be calculated using the formula:

P(failure on demand) = 1 - e^(-λt)

Where λ is the failure rate (in this case, 1/5 years = 0.2 failures per year) and t is the time between tests (5 years). Plugging in these values gives:

P(failure on demand) = 1 - e^(-0.2 * 5)

= 1 - e^(-1)

= 1 - 0.3679

≈ 0.6321

This computation reveals that the probability of failure on demand for the control valve, when tested every five years and with a dangerous failure rate of one every five years, is approximately

More practice questions